*EducationWorld is pleased to present this article contributed by George Alland, Rasmussen College instructor at the Brooklyn Park, MN campus. Alland teaches students seeking degrees in business, education, health sciences and other areas.*

Some students in my introductory algebra class struggle with basic concepts. Based on my lessons learned with this diverse group of learners, following are some tips for teaching algebra to a general audience.

**Solving Equations**

After explaining the basic concepts in solving equations, I show students a simple equation to solve such as 2*x* + 4 = 8. I tell students that the goal is to get* x* by itself on one side of the equation. So the first step is to subtract 4 from both sides, and we are left with 2*x* = 4. Most are able to follow this procedure. Then when I ask them what should be the next step, some students want to subtract the 2 from the 2*x*. So I explain that 2*x* means 2 multiplied by *x*, so to get *x* by itself we need to divide by 2. This satisfies some students but others remain confused.

I have achieved good results by turning this equation into a word problem: Two cantaloupes = $4. I ask “How much is one cantaloupe?” and they all answer $2. Then I ask “How did you figure this out?” This helps them realize that they had to divide both sides by 2 in order to get the answer.

**Collecting Like Terms**

I use a similar strategy when I am explaining how to add like terms. For example, if we have an expression such as 6*x*^{2} + 2*x*^{4} - 2*x*^{2} + 7 + 3*x*^{2} - 3 and the goal is to combine like terms, I first ask three students to name their favorite fruit. If I get answers such as apples, oranges and bananas, I first rewrite this expression as 6 apples + 2 oranges – 2 apples + 7 bananas + 3 oranges - 3 bananas. Then I ask them to evaluate how many fruits of each kind are left. Most can figure this out as 4 apples + 5 oranges + 4 bananas.

Then I tell students that in math we also have different kinds of fruits but they have mathematical names such as *x*^{4}, *x*^{2} and just plain numbers. They are then usually able to make the connection and get the right answer.

**Factoring Polynomials**

Most algebra textbooks introduce factoring of polynomials before describing the purpose of factoring. I prefer to start by showing my students a graph of a quadratic equation which is a parabola, and explaining that the solutions of this quadratic are the x intercepts (they are already familiar with the concept of intercepts from linear equations). Then I indicate that there are three ways of solving this type of equation: 1) The quadratic formula, 2) completing the square and 3) factoring (when possible). Then the reason for factoring becomes more understandable in view of the ultimate goal.

**Systems of Equations**

Before showing the two methods of solving a system of two equations (substitution and elimination), I first write this equation on the board: *x* + *y* = 4.

Then I ask my students “What is x and what is y?” After the common answers of 2 and 2, 3 and 1 and 4 and 0, most of them soon realize that an equation in two variables does not have a unique solution, because there are an infinite number of possible answers. Then I write two equations like this:

*x* + *y* = 4*x* -* y* = 2

I ask “What is x and what is y?” Most are able to figure out that x is 3 and y is 1. This makes the explanation that we need two equations to solve for x and y more understandable.

**Finding the LCM (Least Common Multiple) of Rational Expressions**

This topic is often quite challenging for students. What I try to do is clearly demonstrate the analogy with finding the LCM of numbers, which they have studied in an earlier chapter and know fairly well by the time we get to rational expressions.

In order to find the LCM of 12, 15 and 18, break each number down into its prime factors:

**12**: 3,2,2**15**: 3,5**18**: 3,3,2

So the LCM is 3 x 3 x 2 x 2 x 5 = 180

To find the LCM of *x*^{2} - 4, *x*^{2} + 4*x* + 4, 2*x* - 4, break each expression into its prime factors (after defining a prime factor for an algebraic expression):

*x*^{2} - 4: (*x* + 2) (*x* - 2)*x*^{2} + 4*x* + 4: (*x* + 2) (*x* + 2)

2*x* - 4: 2(*x* - 2)

Using the same procedure we used for numbers, we pick each prime factor to the maximum number of times it appears in any of the three expressions:

So the LCM is 2(*x* + 2) *(x* +2) (*x* - 2)

As opposed to with numbers, we don’t usually multiply out all the terms together.

**What is the Meaning of “=” (Equals)? **

In one lecture on the distributive property I wrote the following equation on the board: 2(*x* + 3) = 2*x* + 6

One student asked “But what is the answer?” I did not at first understand what the student was getting at, and I asked her to explain. She said she was told in her previous math classes in high school that equations always have an answer, so what is the answer here? Then I realized that “equals” has actually two meanings. In one case if I write *x* + 2 = 6 then the answer is *x* = 4. But in the equation above, the right side is a transformation of the left side—a transformation into an equivalent but differently formatted expression. Since then, I always make my students aware of the different uses of the term “equals.”

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